a motorbike is travelling with a velocity of 3m/s. It accelerates at a rate of 9.3m/s for 1.8s. Calculate the distance it travels in this time.

S = 20.46m

Explanation:

According to Second Law of Motion:

S = Vi*t + 0.5*a*t^2

dа ta:

Vi = 3m/s

a = 9.3m/s^2

t = 1.8s

S = ?

Solution:

S = 3*1.8 + 0.5*9.3*1.8^2

S = 5.4 + 15.06

S = 20.46m