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31 August, 11:26

You accidently throw your car keys horizontally at 8.0 m/s form a cliff 64m high. How far from the base of the cliff should you look for the keys?

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  1. 31 August, 11:56
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    The formula that applies to the problem is this equation on projectile motion expressed as:

    y = x tan θ - ½ g x2 / (v0 cos θ) ^2.

    We are given with y equal to 64 m, θ is zero degrees and vO equal to 8.0 m/s. By substitution, the x then is equal to 28.91 meters.
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