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12 June, 07:38

Solve for x and y simultaneously x-2y=3. 3x²-5xy-16y=24

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Answers (2)
  1. 12 June, 08:12
    0
    X-2y=3 ⇒y = (x-3) / 2

    3x²-5xy-16y=24

    We can suggest this system of equations by substitution method.

    y = (x-3) / 2

    3x²-5x (x-3) / 2-16 (x-3) / 2=24

    least common multiple=2

    6x²-5x (x-3) - 16 (x-3) = 48

    6x²-5x²+15x-16x+48=48

    x²-x=0

    x (x-1) = 0

    Now, we solve two equations:

    1) x=0 ⇒y = (0-3) / 2=-3/2

    2) x-1=0

    x=1 ⇒y = (1-3) / 2=-1

    Answer: we can two solutions:

    solution1: x=0; y=-3/2

    solution2: x=1, y=-1
  2. 12 June, 08:42
    0
    Hello,

    x=3+2y

    ==> 3 (3+2y) ²-5 (3+2y) y-16y=24

    ==>2y²+5y+3=0

    ==> (y=-3/2 and x = 0 or y=-1 and x=1)

    sol={ (0,-3/2), (1,-1) }
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