The velocity graph of a car accelerating from rest to a speed of 75 km/h over a period of 30 seconds is shown. Estimate the distance traveled during this period. (Use M6 to get the most precise estimate. Round your answer to two decimal places.)

Question

Mathematics

Makena Mullen

20 March, 23:39

The velocity graph of a car accelerating from rest to a speed of 75 km/h over a period of 30 seconds is shown. Estimate the distance traveled during this period. (Use M6 to get the most precise estimate. Round your answer to two decimal places.)

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Charlee Stafford · Answer 1

To calculate the distance travelled, we have to use the equations of motion: V = U + f*t and S = U*t + (1/2) * f*t*t where u and v are initial and final velocities, f the acceleration and t is time taken. Here u = 0 as the car starts from rest, V = 75 km/hr and t = 30 sec. Converting V to meter / sec and substituting in above equations, we get f = (25/36) = 0.6944m / sec * sec. Putting this in 2nd equation distance S = 312.5 meters or 0.3125 km.