A baseball diamond is a square with sides of 90 feet. What is the shortest distance, to the nearest tenth of a foot, between first and third base?

127.3 feet This problem requires the use of pythagoras theorem. Ignore the face that it's a baseball diamond. All you're concerned with is that you have a square that's 90 feet per side and you want to know what the length of the diagonal. So you have a right triangle with 2 sides of 90 feet each and you want to know the length of the hypotenuse. The formula is C^2 = A^2 + B^2 Both A and B are 90, so plugging them into the formula gives C^2 = 90^2 + 90^2 = 8100 + 8100 = 16200 So C^2 = 16200 Take the square root of both sides C = 127.2792 Round to the nearest tenth, giving C = 127.3