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13 September, 04:13

The probability of being in a car accident when driving more than 10 miles over the speed limit in a residential neighborhood is 0.07. of the next 1,698 cars that pass through a particular neighborhood, what are the first and third quartiles for the number of car accidents in this neighborhood?

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  1. 13 September, 04:22
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    We are given the following values:

    n = number of samples / cars = 1,698

    p = probability of each success = 0.07

    The standard deviation (σ) is calculated using the formula:

    σ = sqrt [n p (1 - p) ]

    σ = sqrt [1,698 (0.07) (1 - 0.07) ]

    σ = 10.51

    The mean (x) is:

    x = n p

    x = 1,698 (0.07)

    x = 118.86 car accidents

    The quartiles are:

    1st quartile = x - 2σ to x - σ

    1st quartile = 118.86 - 2 (10.51) to 118.86 - 10.51

    1st quartile = 97.84 to 108.35

    (97.84
    3rd quartile = x to x + σ

    3rd quartile = 118.86 to 118.86 + 10.51

    3rd quartile = 118.86 to 129.37

    (118.86
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