A jeweler maker has 20 ounces of a gold alloy worth $160 an ounce and 10 ounce of a silver alloy worth $140 an ounce. How many ounces of another alloy at $124 an ounce must she add to these in order to have a mixture of the three that she can use to make 3-ounce jewelry worth $438 a piece?

For this case he does not need anything of $ 124 / oz. Let's prove it.

Let

x = gold alloy required

(3-x) = silver alloy required

160x + 140 (3-x) = 438

160x + 420 - 140x = 438

160x - 140x = 438 - 420

20x = 18

x = 18/20

x = 0.9 oz gold alloy

3 - 0.9 = 2.1 oz silver alloy

We check the result:

0.9 (160) + 2.1 (140) =

144 + 294 = 438

answer:

No ounces of another alloy at $ 124 an ounce must she add to these in order to have a mixture of the three that she can use to make 3-ounce jewelry worth $ 438 a piece