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13 January, 07:13

Find an equation in standard form for the hyperbola with vertices at (0, ±2) and foci at (0, ±7).

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  1. 13 January, 08:49
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    Standard Form of an Equation of an Hyperbola opening up and down is:

    (y-k) ^2 / b^2 - (x-h) ^2 / a^2 = 1

    where Pt (h, k) is a center with vertices 'b' units up and down from center.

    vertices: vertices: (0,+-2) b = 2 AND Center is (0,-0)

    (y) ^2/4 - (x) ^2/a^2=1

    foci: (0,+-7)

    a^2 = 24

    square root of 4 + a^2 = 5.29

    4 + 5.29 = 9.29

    y^2 / 4 - x^2 / 24 = 1
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