The diagonals of a rhombus are 12cm and 16cm long find the the perimeter and area of the rhombus

To solve this integral, what you can do is split it up as follows: (1) ∫40 (x2-4) dx=∫40 (x2) dx-∫40 (4) dx. To integrate 4 as an indefinite integral, a good rule of thumb is by an equation below for polynomials;. (2) ∫xa=xa+1a+1 + C, where a is any number. C denotes some constant that is crucial when doing ...

Given the diagonals are 12cm and 16cm

⇒ Area = 1/2 (12 x 16) = 96 cm²

Find side of the rhombus:

a² + b² = c²

c² = 6² + 8²

c² = 100

c = √100

c = 10

Perimeter = 4 x 10 = 40 cm

Answer; Area = 96 cm², Perimeter = 40 cm