The product of 2 consecutive #s is 4160 what are the numbers?

So the so the product of two consecutive numbers is 4160 or

x (x+1) = 4160

distribute

x^2+x=4160

subtract 4160 from both sides

x^2+x-4160=0

find the factor (if you want to know how, just ask in the comments)

(x-64) (x+65) = 0

so the answer is x could be 64 or - 65

so the number that work are 64,65 and - 65,-64

64 multiplied by 65 is equal to 4160. You can zero in on the right combination using guess and check.