If possible, find the area of the triangle defined by the following:

b = 45, c = 20, a = 71°.

a.) 465.4 square units

b.) 189.1 square units

c.) 425.5 square units

d.) 405.2 square units

I'd really like to know which of these is correct.

Given that the area has two sides and one angle measure given by:

b=45, c=20 and A=71°

The area of the triangle will be given by:

Area=1/2ab sin theta

Area=1/2*45*20*sin 71

Area=425.48 square units

=425.5 square units

The answer is C. 425.5 square units