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30 April, 10:34

Human body temperatures are normally distributed with a mean of 98.20°f and a standard deviation of 0.62of. find the temperature that separates the top 7% from the bottom 93%. round your answer to the nearest hundredth.

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  1. 30 April, 10:49
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    Find the probability area bound by 93% or 0.93.

    0.5 lies to the left of the mean value.

    0.93-0.5=0.43 lies to the right of mean.

    Find the corresponding z value for 0.43.

    It is 1.48.

    Use this value to determine the required x value.

    You have to use the formula -

    z = x-μ σ

    Solve it for x

    x=z⋅σ+μ

    Where;

    x=?

    z=1.48

    σ=0.62

    μ=98.20

    Now put these values in the formula;

    x = (1.48⋅0.62) + 98.20=0.9176+98.20=99.1176 = 99.12

    Temperature that separates top 7% from the bottom 93% is 99.12.
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