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30 January, 02:49

A cardboard sheet is cut in the shape of a triangle, with vertices at (0,0), (20,0), and (3,4) units. the thickness of the sheet is uniform. what is the x-coordinate of its center of mass?

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  1. 30 January, 05:59
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    This problem can be solved in two ways, the long way, or the short way.

    1. The long way

    We know that the base of the triangle is along the x-axis, and the length of the base is 20.

    The centre of mass is located at 2/3 of the distance from vertex (3,4) along the median, which cuts the base at (10,0).

    Therefore the centre of mass is located at

    x=3 + (10-3) * 2/3=23/3

    y=4/3

    2. The short way

    It turns out that the centre of mass of a triangle sheet is located at the mean of the coordinates of the three vertices, i. e.

    CG = ((0+20+3) / 3, (0+0+4) / 3) = (23/3, 4/3) as before.
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