A ball is thrown horizontally at a speed of 24 meters per second from the top of the building. If the ball hits the ground 4.0 seconds later approximately how high is the building? ... ?

The problem indicates that the ball was thrown horizontally. Therefore Vox is 24 m/s and Voy = 0

Yo = initial eight where the ball is coming from

Y is the final height or the ground

The formula will be like this,

Y=Yo+Voy t - (1/2) gt^2 with that said Voy t = 0 since Voy=0,

With the height or Y = 0

0=Yo - (1/2) gt^2

Yo = (1/2) gt^2

then solve the equation and it will look like this,

Yo = (1/2) (9.8 m/s^2) [ (4s) ^2]

Then the answer would be

Yo = 78.4 m