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28 January, 22:26

A car tire has a radius of 15 inches. Suppose the car is traveling at 60 miles per hour (1 mile = 5,280 feet). What is the approximate rate of spin, in revolutions per minute, of the tire? Round the answer to the nearest whole number.

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Answers (2)
  1. 29 January, 01:25
    0
    Radius = r = 15 inches

    Speed of the car = v = 60 miles per hour

    = 60 x 5280 feet per hour

    = 316800 feet per hour

    = 316800 x 12 inches per hour

    = 3801600 inches per hour

    = 3801600/60 inches per minute

    = 63360 inches per minute

    Angular velocity = w = ?

    v = r w

    w = v/r

    So,

    w = 63360/15

    = 4224 radians per minute

    = 4224/2π revolutions per minute

    = 672 revolutions per minute

    So, the angular velocity of the tire is 672 revolutions per minute
  2. 29 January, 01:46
    0
    First find the distance covered in 1 revolution,

    Circumference = 2π*15/12 = 7.85398 feet. (1 foot=12 inches)

    7.85398 feet = 7.85398/5280 = 0.001487496522 miles

    In 1 hour, it travels 60 miles. This means it travels (60/60) miles in 1 minute.

    So, it travels 1 mile in 1 minute.

    The rate of rotation = 1/0.001487496522

    = 672.27rpm

    To the nearest whole number = 672 rpm
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