The sum of three consecutive integers is 141. what is the smallest integer

Integer 1 = n

integer 2 = n + 1

integer 3 = n + 2

n + (n + 1) + (n + 2) = 141

3n + 3 = 141

3n = 141 - 3

3n = 138

n = 138/3

n = 46 - - (1st integer)

n + 1 = 46 + 1 = 47 - - (2nd integer)

n + 2 = 46 + 2 = 48 - - (3rd integer)

so the smallest integer is 46