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10 October, 15:29

H^2+14h=-31 Solve by completing the square

write your answers as integers, proper or improper fractions in simplest form, or decimals rounded to the nearest hundredth

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Answers (2)
  1. 10 October, 16:25
    0
    Given H^2+14h=-31, let's complete the square of the 1st two terms:

    h^2 + 14h + (14/2) ^2 = - 31 + (14/2) ^2

    h^2 + 14h + 49 = - 31 + 49 = 18

    (h+7) ^2 = 18

    Taking the sqrt of both sides,

    h+7 = sqrt (9*2) = 3 sqrt (2)

    Solving for h, h = - 7 plus or minus 3 sqrt (2) (answer)
  2. 10 October, 16:40
    0
    Since the constant has been moved to the left side, you can move on to the next step which is adding (b/2) ² to both sides of the equation.

    h² + 14h + (14/2) ² = - 31 + (14/2) ²

    Simplify the parenthesis and exponent.

    h² + 14h + 7² = - 31 + 7²

    h² + 14h + 49 = - 31 + 49

    h² + 14h + 49 = 18

    Factor the expression of the left.

    (h + 7) (h + 7) = 18

    Take the square root of both sides.

    √ (h + 7) (h + 7) = ± √9 • 2

    (h + 7) = ± 3√2

    h + 7 = ± 3√2

    Subtract 7 from both sides.

    You solutions are:

    h = - 7 + 3√2 → - 2.7573 → - 2.76

    h = - 7 - 3√2 → - 11.2426 → - 11.24
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