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5 July, 20:12

If the police have 9 suspects how many different ways can they select 5 for a lineup

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  1. 5 July, 21:14
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    Assuming the order does not matter, you want the number of combinations of 9 things taken 5 at a time. The combinations can be shown as C (9,5), 9C5.

    C (9, 5) =

    9/5 (9-5) =

    9*8*7*6*5 / 5*4

    The 5 terms cancel.

    9*8*7*6 / 4*3*2 =

    9*7*2 =

    126

    The above change is because 4*2 cancels the 8 in the numerator and 6/3 = 2

    Therefore, the solution is 126.
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