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27 October, 08:08

Solve the following system of liner equations:

6x - 3y + 10 = 0

2x + y + 9 = 0

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Answers (1)
  1. 27 October, 10:17
    0
    First we get the value of y in terms of x

    We have 2x + y + 9 = 0

    We transpose 2x and 9 to the other side so we could get the value of y being:

    y = - 2x - 9

    Now that we have the value of y we can substitute it to the first equation

    6x - 3y + 10 = 0

    6x - 3 (-2x - 9) + 10 = 0

    Simplifying the inside of the parentheses we would have

    6x - (3) (-2x) - (3) (-9) + 10 = 0

    6x + 6x + 27 + 10 = 0

    Combining similar terms we would get

    12x + 37 = 0

    We transpose 37 to the other side for easier simplification

    12x = - 37

    We divide both sides by 12 to get the value of x

    12x/12 = - 37/12

    Since 12/12 is equal to 1 our value of x would be

    x = - 37/12

    Or simply x = - 3.0833

    Now that we know the value of x we can use it to obtain the value of y

    y = - 2x - 9

    y = - 2 (-37/12) - 9

    y = 37/6 - 9

    y = - 17/6

    Or in decimal y = - 2.8333

    Final values of x and y would be

    x = - 3.0833

    y = - 2.8333
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