Ask Question
15 April, 19:02

Each day, Steve walked 1/12 mile more than the previous day. The first day he walked 1/12, the second day he walked 2/12 mile, the third day he walked 3/12 mile. On which day did the sum of his walks total at least 1 complete mule?

+1
Answers (1)
  1. 15 April, 22:47
    0
    1st day = 1/12

    2nd day = 2/12

    3rd day = 3/12

    4th day = 4/12

    5th day = 5/12

    6th day would be = 6/12

    If it continues in that order, the sum of the walks would total 1 mile when:

    They all add up to 12/12

    Add = 1/12 + 2/12 + 3/12 + 4/12 = 10/12

    That is still not up to 12/12

    So we add up the 5th day also = 10/12 + 5/12 = 15/12 = 1 3/12 miles

    So on the 5th day the sum of his walks total at least 1 completed mile.

    At least 1 means 1 and above. As you can see the answer we got 1 3/12 is already more than 1.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Each day, Steve walked 1/12 mile more than the previous day. The first day he walked 1/12, the second day he walked 2/12 mile, the third ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers