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Mathematics
Bethany Vance
20 October, 07:52
If y = 1 i, then y3 - 3y2
+3
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Emery Pollard
20 October, 10:19
0
Y = 1i = i
y³ - 3y²
(i) ³ - 3 (i) ² i ² = - 1, i³ = i² (i) = - i
i³ - 3i²
-i - 3 (-1)
-i + 3
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Braedon Dean
20 October, 11:03
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Y^3-3y^2
(1+i) ^3-3 (1+i) ^2
remember
(1+i) ^3 = (1+i) (1+i) ^2
(1+i) (1+i) ^2-3 (1+i) ^2
factor out (1+i) ^2
(1+i) ^2 ((1+i) - 3)
(1+i) ^2 (1+i-3)
(1+i) ^2 (i-2)
(1+i) (1+i) (i-2)
(1+2i-1) (i-2)
(2i) (i-2)
-2-4i
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