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10 November, 13:04

Three friends were born in consecutive years. The some of their birth years is 5982. find the year in which each person was born

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  1. 10 November, 14:37
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    A+b+c=5982

    find the average of the three friends

    5982/3=1994

    add and subtract one to find the average

    1994+1=1995

    1994-1=1993

    add all the years together to check

    1993+1994+1995=5983
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