Y=x^2+3x+29 how do you complete the square

X^2 + 3x + 29 = 0

To complete the square:

Move "non-x" term to the right

x^2 + 3x = - 29

Divide equation by coefficient of x^2

(the equation already had the x^2 coefficient as 1)

Take coefficient of x

divide it by 2

square it

add it to both sides of equation

3

3/2 = 1.5

1.5^2 = 2.25

x^2 + 3x + 2.25 = - 29 + 2.25

Taking square root of both sides

(x + 1.5) = sq root (-26.75)

square roots of negative numbers are complex (I don't know how to do that).