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1 March, 17:12

A box is launched upward from the ground at a speed of 57 feet per second. Calculate the height in feet of the box at 3 seconds. use g=32 ft/s^2 as the acceleration due to gravity

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  1. 1 March, 18:46
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    The vertical height traveled is given by

    h = ut + - (1/2) g*t^2

    where

    u = 57 ft/s, initial speed

    t = tme, s

    g = 32 ft/s^2

    After 3 seconds,

    h = (57 ft/s) * (3 s) - (1/2) * (32 ft/s^2) * (3 s) ^2

    = 171 - 144

    = 27 ft

    Answer: 27 ft
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