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10 July, 23:06

Solve the following system by the elimination method. Check the solution.

5x-5=-7y, 6x+5y=-11

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Answers (2)
  1. 10 July, 23:21
    0
    I assume elimination method is to eliminate one of the variables. in order to eliminate one then that variable must have the same coefficient in both equations. I look at what will be easier to eliminate. The x values look easier with 6 and 5. in order to make them equal I must multiply each equation by the other equations x coefficient. (remember that to multiply an equation by a number is to multiply both sides of the equal sign by that number.)

    so:

    6 (5x-5) = 6 (-7y)

    30x - 30 = - 42y

    5 (6x+5y) = 5 (-11)

    30x + 25y = - 55

    now I subtract the 2 equations.

    I will subtract the left sides of equations and subtract the right sides of equations on other side

    30x - 30 - (30x + 25y) = - 42y - (-55)

    distribute the minus sign into the parenthesis

    30x - 30 - 30x - 25y = - 42y + 55

    cancel out the x values

    - 30 - 25y = - 42y + 55

    solve for t

    17y = 85

    Y = 5

    plug y into either equation

    6x + 5 (5) = - 11

    6x + 25 = - 11

    6x = - 36

    x = - 6

    answer (5,-6)

    this can be checked by plugging the values into other equatiin
  2. 11 July, 02:20
    0
    Hmm

    add 7y+5 to both sides of 1st equation

    5x+7y=5

    eliminate x's

    multiply first equation by - 6 and 2nd by 5 and add them

    -30x-42y=-30

    30x+25y=-55 +

    0x-17y=-85

    -17y=-85

    divide both sides by - 17

    y=5

    sub back

    5x-5=-7y

    5x-5=-7 (5)

    5x-5=-35

    add 5

    5x=-30

    divide 5

    x=-6

    x=-6

    y=5

    subsitute to find out

    5x-5=-7y

    5 (-6) - 5=-7 (5)

    -30-5=-35

    -35=-35

    yep

    6x+5y=-11

    6 (-6) + 5 (5) = - 11

    -36+25=-11

    -11=-11

    yep

    x=-6

    y=5

    (-6,5)
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