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27 November, 18:52

At Jefferson High School, a student takes 4 core classes a day. There are 6 different core classes offered. How many different combinations of classes are there? 12 combinations 15 combinations 24 combinations 10 combinations

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  1. 27 November, 22:12
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    Order does not matter so you would want to use the "n choose k" equation:

    n! / (k! (n-k) !), where n=number of possible choices and k=number of selections

    In this case:

    6! / (4! (6-4) !)

    6! / (4!*2!)

    15

    So there are 15 unique combinations of classes possible.
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