The flight of a cannonball toward a hill is described by the parabola y = 2 + 0.12x - 0.002x 2. the hill slopes upward along a path given by y = 0.15x. where on the hill does the cannonball land?

To find where on the hill the canonball lands

So 0.15x = 2 + 0.12x - 0.002x^2

Taking the LHS expression to the right and rearranging we have - 0.002x^2 + 0.12x -

0.15x + 2 = 0.

So we have - 0.002x^2 - 0.03x + 2 = 0

I'll multiply through by - 1 so we have

0.002x^2 + 0.03x - 2 = 0.

This is a quadratic eqn with two solutions x1 = 25 and x2 = - 40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75