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6 September, 05:27

Three consecutive integers exist where the smallest is fifteen less than twice the larger. Find the integers

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  1. 6 September, 06:26
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    Consecutive integers are integers that appear one after the other. so let's call them x, x+1, and x+2.

    the smallest (which is x) is 15 less than twice the larger. "the larger" is a bit unclear, but i'm assuming it is referring to the x+1 integer, because it doesn't say the "largest". so x = 2 (x+1) - 15. let's try to solve for x.

    x = 2 (x+1) - 15

    x = 2x + 2 - 15

    x = 2x - 13

    subtract 2x from both sides.

    -x = - 13

    x = 13

    x+1 = 14

    x+2 = 15

    your integers are 13, 14, and 15.
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