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28 June, 19:50

Using the principle of inclusion-exclusion, the number of integers between 1 and 2000 (inclusive) that are divisible by at least one of 2, 3, 5, 7 is

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  1. 28 June, 21:32
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    For all integers x ∈ [1,2000]

    N (2|x) = 2000/2=1000

    N (3|x) = 2000/3=666

    N (5|x) = 400

    N (7|x) = 285

    Total = 2351

    N (2|x & 3|x) = N (6|x) = 333

    N (15|x) = 133

    N (35|x) = 57

    N (10|x) = 200

    N (14|x) = 142

    N (21|x) = 95

    total = 960

    N (2|x & 3|x & 5|x) = N (30|x) = 66

    N (42|x) = 47

    N (70|x) = 28

    N (105|x) = 19

    total=160

    N (2|x & 3|x & 5|x & 7|x) = N (210|x) = 9

    total=9

    By the inclusion/exclusion principle, numbers of integers between 1 and 2000 divisible by at least one of 2,3,5,7

    = 2351-960+160-9

    =1542
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