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2 August, 08:30

Solve 8y-3 (4-2y) = 6 (y+1)

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Answers (2)
  1. 2 August, 08:57
    0
    8y - 3 (4 - 2y) = 6 (y + 1)

    Step 1: Simplify both sides of the equation.

    8y - 3 (4 - 2y) = 6 (y + 1)

    8y + (-3) (4) + (-3) ( - 2y) = (6) (y) + (6) (1) (Distribute)

    8y + - 12 + 6y = 6y + 6 (8y + 6y) + (-12) = 6y + 6 (Combine Like Terms)

    14y + - 12 = 6y + 6

    14y - 12 = 6y + 6

    Step 2: Subtract 6y from both sides.

    14y - 12 - 6y = 6y + 6 - 6y

    8y - 12 = 6

    Step 3: Add 12 to both sides.

    8y - 12 + 12 = 6 + 12

    8y = 18

    Step 4: Divide both sides by 8. 8y / 8 = 18/8

    y = 9/4

    Answer: y = 9 / 4
  2. 2 August, 11:05
    0
    Y=9/4 that's a fraction
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