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Mathematics
Trystan Bradshaw
22 May, 01:25
Calculate dy/dx if y = Ln (2x3 + 3x).
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Tessa Frey
22 May, 02:38
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Differentiate using the chain rule:
d/du [ln (u) ] d/dx[2x^3+3x]
derivative of ln (u) = 1/u
1/u d/dx[2x^3+3x]
1/2x^3+3x d/dx[2x^3+3x]
Differentiate
(6x^2+3) 1/2x^3+3x
Simplify
Dy/dx = 3 (2x^2+1) / x (2x^2 + 3)
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