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10 June, 19:38

The table shows data for a car stopping on a wet road.

v d

20 38

30 86

40 153

stopping distance formula d (v) = 2.15v2/64.4f

Determine the value of f, rounded to the nearest hundredth.

+5
Answers (1)
  1. 10 June, 22:36
    +1
    First, rearrange the formula to make 'f' the subject

    d (v) = 2.15v^2 : 64.4f

    64.4f = 2.15v^2 : d (v)

    f = 2.15v^2 : 64.4d (v)

    When d (v) = 38 and v = 20

    f = 2.15 (20) ^2 : 64.4 (38)

    f = 0.35

    When d (v) = 86 and v = 30

    f = 2.15 (30) ^2 : 64.4 (86)

    f = 0.35

    When d (v) = 153 and v = 40

    f = 2.15 (40) ^2 : 64.4 (153)

    f = 0.35

    So f is a constant 0.35
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