Your friend rent 10chairs and 2 tables for $300. another friend rent 8 chairs and 4 tables for $360 you want to rent 12 chairs and 3 tables how much do you expect to pay? ps I need it today

If x is chairs and y is tables then

10x+2y=300

8x+4y=360

solve for y and substitute to find x

10x+2y=300

2y=300 - 10x

y=150 - 5x so put 150 - 5x in for y in the other equation

8x+4 (150-5x) = 360

8x+600-20x=360

-12x=-240

x = $20 per chair

put that in for x in either equation to find y

10 (20) + 2y=300

2y=300-200

y=100/2

y = $50 per table

12 chairs and 3 tables would cost 12 (20) + 3 (50) = 240+150=

$390