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4 April, 09:47

If an object is propelled upward from a height of s feet at an initial velocity of v feet per second, then its height h after t seconds is given by the equation hequals=minus-16t squaredt2plus+vtplus+ s, where h is in feet. if the object is propelled from a height of 88 feet with an initial velocity of 6464 feet per second, its height h is given by the equation hequals=minus-16t squaredt2plus+6464tplus+88. after how many seconds is the height 3636 feet?

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  1. 4 April, 12:22
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    Im sorry i have no idea i think it would be half the time of 6464 ft per second
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