Ask Question
3 March, 15:20

Joe's annual income has been increasing each year by the same dollar amount. The first year his income was $20,400 and the 11th year his income was $31,400. In which year was his income $40,200?

+1
Answers (1)
  1. 3 March, 18:10
    0
    Answer: 18th year

    In this question, the income is increasing each year with the same amount, first-year income is $20,400 and 11th-year income is $31,400. From this information, you can determine how much the income increases every year. The calculation would be:

    Income year Y = first income + { (Y-1) * income increase per year) }

    $31,400 = $20,400 + 10 * income increase per year

    10 * income increase per year = $11000

    income increase per year = $1100

    Using the same formula you can find the answer

    Income year Y = first income + { (Y-1) * income increase per year) }

    $40,200 = $20,400 + Y * 1100

    1100Y = 40,200-20,400 = 19800

    Y = 19800/1100 = 18 year.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Joe's annual income has been increasing each year by the same dollar amount. The first year his income was $20,400 and the 11th year his ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers