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24 January, 20:23

Micky is trying to solve the following problem but, he missed the lesson. In complete sentences, describe how you woukd solve the following problem. 6|2x-14|=42

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  1. 24 January, 21:18
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    First the two lines on either side of I2x-14I shows us that 2x-14 needs to be in the absolute form which would be 2x+14 because the absolute form is just referring to the numeral amount that a number or equation etc is from 0. Once you have done this you will now have 6 (2x+14) = 42. Now use the distributive property first multiplying 6 by 2x to come up with 12x then multiplying 6 with 14 to come up with 84. This leaves you with 12x+84=42. Next, subtract 84 from both sides of the equation to come up with 12x=-42. Finally, divide both sides of the equation by 12 to come up with x = - 3.5
  2. 24 January, 23:26
    0
    We must solve for x. Let's simplify this equation by dividing both sides by 6:

    |2x-14|=7, which is the same as 2|x-7|=7.

    First, assume that x-7 is already positive, so that we don't need the absolute value operator. Then x-7=7/2. Adding 7 to both sides results in x = 21/2.

    Next, find the other solution:

    Assume that x-7 is negative. Then |x-7| = - (x-7). Then - (x-7) = 7,

    and - x + 7 = 7. Thus, x = 0.

    The solution set is {0, 21/2}.
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