Suppose f (x) = x^-1. find the graph of f (2/3x)

To solve this question, you need to put the 2/3x into the f (x). Remember that x^-1 equal to 1/x

Assuming 2/3x is 2/3 * x, the calculation would be:

f (x) = x^-1

f (2/3x) = (2/3*x) ^-1.

f (2/3x) = 1 / (2x/3)

f (2/3x) = 3 / (2x)

Assuming 2/3x is 2 / (3x), the calculation would be:

f (x) = x^-1

f (2/3x) = (2/3x) ^-1.

f (2/3x) = 1 / (2/3x)

f (2/3x) = 3x/2