In basketball, when monica takes her first free throw, she has a 50% chance of scoring. if she takes an additional throw, she has a 75% chance of scoring on this throw if she scored on the immediately previous throw, but only a 25% chance of scoring on this throw if she didn't score on the immediately previous throw. suppose she has to take a set of three free throws in a row, and she doesn't score on the first one. what is the probability that she scores at least once on one of the subsequent two throws?

Question

Mathematics

Theodore Gibbs

16 February, 05:22

In basketball, when monica takes her first free throw, she has a 50% chance of scoring. if she takes an additional throw, she has a 75% chance of scoring on this throw if she scored on the immediately previous throw, but only a 25% chance of scoring on this throw if she didn't score on the immediately previous throw. suppose she has to take a set of three free throws in a row, and she doesn't score on the first one. what is the probability that she scores at least once on one of the subsequent two throws?

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Justice Hartman · Answer 1

The probability that she scores at least once on one of the subsequent two throws is 37.5%. It is said that on the first row, she has a 50% chance of scoring. If she takes an additional throw, she has a 75% chance of scoring on this throw if she scored on the immediately previous throw, but only a 25% chance of scoring on this throw if she didn't score on the immediately previous throw. You are asked if she has to take a set of three free throws in a row, and she doesn't score on the first one and so multiply 75% by 50% and you will get 37.5%.