Sanjay and Felipe are putting together a 500-piece puzzle. Sanjay could do the entire puzzle by himself in 6 hours, while it would take Felipe 8 hours to do the puzzle alone.

Use the table to write and solve an equation to determine the approximate amount of time it would take Sanjay and Felipe to do the puzzle if they were working together.

0.8 hours

1.7 hours

3.4 hours

7 hours

Question

Mathematics

Guest

25 May, 15:09

Sanjay and Felipe are putting together a 500-piece puzzle. Sanjay could do the entire puzzle by himself in 6 hours, while it would take Felipe 8 hours to do the puzzle alone.

Use the table to write and solve an equation to determine the approximate amount of time it would take Sanjay and Felipe to do the puzzle if they were working together.

0.8 hours

1.7 hours

3.4 hours

7 hours

+5

Answers (1)

Know the Answer?

Caiden Deleon · Answer 1

3.4 hours. The efficiency of a worker is the amount of work divided by time needed. The efficiency of Sanjay alone is 500/6, and the efficiency of Felipe alone is 500/8. When they work together, their combined efficiency is 500/6+500/8=3500/24. Therefore, they need 500 / (3500/24) = 24/7=3.4 hours.