What is the exact value of x in the exponential equation 2^8x - 3 = 7?

x = log4/8log2

x = 1/8log2

x = 5/8

x = log5/8

Question

Mathematics

Alexandra Chambers

15 March, 23:43

What is the exact value of x in the exponential equation 2^8x - 3 = 7?

x = log4/8log2

x = 1/8log2

x = 5/8

x = log5/8

+1

Answers (1)

Know the Answer?

Dulce Bullock · Answer 1

Hello,

2^ (8x) - 3=7

==>2^ (8x) = 10

==>8x log (2) = log (10)

==>8x log (2) = 1

==>x=1 / (8*log (2))

With parenthesis on the denominator, the answer is B.

What is the exact value of x in the exponential equation 2^8x - 3 = 7?x = log4/8log2x = 1/8log2x = 5/8x = log5/8

What is the exact value of x in the exponential equation 2^8x - 3 = 7?

x = log4/8log2

x = 1/8log2

x = 5/8

x = log5/8