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22 August, 07:55

What are the zeros of the quadratic function f (x) = 6x2 + 12x - 7?

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  1. 22 August, 11:05
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    Use the quadratic formula

    [-12 + / - square root (12^2 - (4) (6) (-7)) ]/2 (6)

    [-12 + / - square root (312) ]/12

    -1 + (1/6) square root (78)

    and

    -1 - (1/6) square root (78)
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