Kevin had 6 nickles and 4 dimes in his pocket. If he took out one count and then a second coin without replacing the first coin-

what is the probability that both coins were nickels?

what is the probability that both coins were dimes?

what is the probability that the first coin was a nickel and the second a dime?

Question

Mathematics

Brent Mcfarland

18 July, 22:44

Kevin had 6 nickles and 4 dimes in his pocket. If he took out one count and then a second coin without replacing the first coin-

what is the probability that both coins were nickels?

what is the probability that both coins were dimes?

what is the probability that the first coin was a nickel and the second a dime?

+3

Answers (1)

Know the Answer?

Aaron Cherry · Answer 1

To find each probability you will state the probability of the first event happening and multiply it by the chance of the second event happening.

P (2 Nickels) : 6/10 x 5/9 = 30/90 (1/3 chance)

P (2 Dimes) : 4/10 x 3/9 = 12/90 (4/30 chance)

P (1 nickel and 1 dime) : 6/10 x 4/9 = 24/90 (8/30 chance)