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14 October, 23:17

What's the answer to find y when x=9 if y varies directly as the square of x, and y = 100 when x = 5

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  1. 15 October, 00:40
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    "y varies directly with square of x"

    y = kx²

    where "k" is the constant of variation you need to solve for first.

    when y = 100; x = 5

    100 = k (5) ²

    100 = 25k

    100/25 = k

    4 = k

    Now you can solve for y when x = 9

    y = 4 (9) ²

    y = 4 (81)

    y = 324
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