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30 July, 04:08

Find the lowest natural number which when divided by 12, 45, 15 and 10 leaves the remainder of

2 in each case.

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  1. 30 July, 05:54
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    12=2*2*3

    45=3*3*5

    15=3*5

    10=2*5

    L. C. M=2*2*3*3*5=180

    required number 180+2=182
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