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13 April, 19:09

For f (x) = x^5-x^3 x what is the equation of the tangent line at x=3?

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  1. 13 April, 22:38
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    F (x) = x^5 - x^3 + x

    f' (x) = 5x^4 - 3x^2 + 1

    f (3) = (3) ^5 - (3) ^3 + 3 = 243 - 27 + 3 = 219

    f' (3) = 5 (3) ^4 - 3 (3) ^2 + 1 = 5 (81) - 3 (9) + 1 = 405 - 27 + 1 = 379

    Let the required equation of the tangent line be

    y = mx + c; where y = 219, m = 379, x = 3

    219 = 379 (3) + c = 1,137

    c = 219 - 1,137 = - 918

    Therefore, required equation is

    y = 379x - 918
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