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Mathematics
Graves
4 October, 20:10
Prove the identity cot^2x/cscx+1=1-sinx/sinx
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Jonah Melton
4 October, 20:32
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Cot²x/csc+1
= (csc²x-1) / (csc+1)
= ((1/sin²x) - 1) / ((1/sinx) + 1)
= ((1-sin²x) / sin²x) / ((1+sinx) / sinx)
= (1-sin²x) / (1+sinx)
= (1+sinx) (1-sinx) / sinx (1+sinx)
= (1-sinx) / sinx
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