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4 October, 20:10

Prove the identity cot^2x/cscx+1=1-sinx/sinx

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  1. 4 October, 20:32
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    Cot²x/csc+1

    = (csc²x-1) / (csc+1)

    = ((1/sin²x) - 1) / ((1/sinx) + 1)

    = ((1-sin²x) / sin²x) / ((1+sinx) / sinx)

    = (1-sin²x) / (1+sinx)

    = (1+sinx) (1-sinx) / sinx (1+sinx)

    = (1-sinx) / sinx
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