Given oblique △ABC

Use the properties of right triangles and △ABC to prove the Law of Sines.

Find the length of BC, rounded to the nearest tenth of a unit.

In your final answer for parts A and B, include all of the necessary steps and calculations.

Law of sines says:

a / sin (A) = b / sin (B) = c / sin (C)

where "a" is a leg of the triangle and "A" is its opposite angle.

You are given an angle of 31 degrees with its opposite leg being a length of 17.

You are then given an angle of 46 degrees and asked to find the length of its opposite side.

So you can create the following equation:

17 / sin (31) = a / sin (46)

Using a calculator to get the value of the sins (I'll round them to 3 digits for now), we get:

17 / 0.515 = a / 0.719

Now solve for a

17 (0.719) = 0.515a 12.223 = 0.515a 12.223 / 0.515 = a a = 23.734

So rounded to tenths of a unit, a = 23.7