The product of two integers is 50. one integer is twice the other. find the integers.

(1) - 5 * (-10) = 50

(2) 5*10=50

Use what they are telling.

a*b=50 (one integer times the other give you a product of 50. we're randomly calling these integers "a" and "b")

2a=b (one integer is twice the amount of the other. we're randomly selecting "b" to be twice the amount of "a")

plug in what we know

a * (2a) = 50 (we replaced "b" with "2a" because we know from the info they gave us that b=2a)

now solve for "a"

a*2a=50

2a²=50

a²=50/2

a²=25

√a²=√25

a=5

which because 2a=b we know that b=10