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2 April, 19:24

Find

dy/du, du/dx, and dy/dx

y = u^2, u=4x+7

+1
Answers (2)
  1. 2 April, 23:08
    0
    Y=u² (du/dx[u^n]=n (u^ (n-1)) u')

    dy/du=2u (u') = 2u

    u=4x+7

    du/dx=4

    dy/dx = (dy/du) (du/dx) = 2u (4) = 2 (4x+7) (4) = 8 (4x+7)

    Answer:

    dy/du=2u

    du/dx=4

    dy/dx=8 (4x+7)
  2. 2 April, 23:19
    0
    dy/dx = 2u

    du/dx==4

    and

    dy/dx = (dy/du) (du/dx)

    =2u (4)

    = 8u
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