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21 May, 13:10

Given the functions j (x) = x2 - 9 and k (x) = - x2 + 7x - 1, which operation results in a 3rd degree polynomial?

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  1. 21 May, 14:21
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    1.] multiplication of x squared by x yields a 3rd degree polynomial (having an x cubed term)

    2.] (x+3) ^1/2 - 4 = x - 1

    (x+3) ^1/2 = x + 3

    square both sides: x+3 = (x+3) ^2

    simplify: x + 3 = x^2 + 6x + 9

    bring all terms to one side so that 0 = x^2 + 5x + 6

    factor the polynomial 0 = (x + 2) (x + 3)

    set each factor equal to zero & solve to get x = - 2 and x = - 3

    3.] x = 4, not extraneous

    4.] In mathematics, complex conjugates are a pair of complex numbers, both having the same real part, but with imaginary parts of equal magnitude and opposite signs. So - 6 - 5i and - 6 + 5i are complex conjugates.

    5.] x = 8 and x = 9

    6.] x to the sixteenth twenty fifth power

    x^4/5 * x^4/5 multiply exponents to get x^16/25

    7.] quantity of 80 minus 50 i over 39
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